9n^2+7n-2=0

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Solution for 9n^2+7n-2=0 equation: 



9n^2+7n-2=0

a = 9; b = 7; c = -2;
Δ = b2-4ac
Δ = 72-4·9·(-2)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-11}{2*9}=\frac{-18}{18}
=-1
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+11}{2*9}=\frac{4}{18}
=2/9
$

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